### 437. Path Sum III 题目: 难度: Easy 思路: ```python class Solution(object): def pathSum(self, root, sum): """ :type root: TreeNode :type sum: int :rtype: int """ if not root: return 0 res = self.auxPathSum(root, sum) res += self.pathSum(root.left, sum) res += self.pathSum(root.right, sum) return res def auxPathSum(self, root, sum): if not root: return 0 if sum == root.val:            # 因为可能有负值, 所以sum为0也会有解, 必须加上            return 1 + self.auxPathSum(root.left, 0) + self.auxPathSum(root.right, 0) else: return self.auxPathSum(root.left, sum - root.val) + self.auxPathSum(root.right, sum - root.val) ```