Python Program to print pattern of Letter D

Hello everyone! Welcome back to programminginpython.com. I am continuing with this pattern programming series, here I will tell you how to print the pattern of the letter ‘D’. In the previous tutorials, I have shown you the pattern for the letter ‘C’, Letter A, and Letter B. Here it’s now time for Pattern D.

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Program on Github

You can also watch the video on YouTube here.

Task:

Python program to print the pattern of letter ‘D’

Approach:

Read an input integer for asking the size of the letter using input()
Check if the entered number is greater than 8,
- if yes, call the function print_pattern()
- else, show a message to enter a number which is greater or equal to 8
print_pattern()
- here we only do two things, print star(*) and print space( ), just writing conditions so the pattern of *‘s and ‘s will display the pattern ‘D’
- following are 3 conditions for printing *’s
  We have 2 loops, outer loop() for rows and inner loop for columns.
- # Outer for loop for row in range(n): # Inner for loop for column in range(n - 2):
  
  1
  2
  3
  4
  5
  
  # Outer for loop
      for row in range(n):
  
          # Inner for loop
          for column in range(n - 2):
  - Print first and last row
    - ((row == 0 or row == n-1) and (0 < column < n-3))
      
      1
      
      ((row == 0 or row == n-1) and (0 < column < n-3))
  - Print first column
    - column == 0
      
      1
      
      column == 0
  - Print last column
    - column == n - 3 and (row != 0 and row != n - 1)
      
      1
      
      column == n - 3 and (row != 0 and row != n - 1)
- print in remaining all cases.

Program on Github

Program:

__author__ = 'Avinash'


# Python3 program to print alphabet pattern D
def print_pattern(n):
  # Outer for loop for number of rows
  for row in range(n):

    # Inner for loop columns
    for column in range(n - 2):

      # prints first and last row
      if (
        ((row == 0 or row == n-1) and (0 < column < n-3)) or

        # prints first column
        column == 0 or

        # prints last column
        column == n - 3 and (row != 0 and row != n - 1)
      ):
        print("*", end=" ")
      else:
        print("  ", end="")
    print()

# Size of the letter
num = int(input("Enter the size \t"))

if num < 8:
  print("Enter a number atleast 8")
else:
  print_pattern(num)

__author__ = 'Avinash'

# Python3 program to print alphabet pattern D

def print_pattern(n):

# Outer for loop for number of rows

for row in range(n):

# Inner for loop columns

for column in range(n - 2):

# prints first and last row

if (

((row == 0 or row == n-1) and (0 < column < n-3)) or

# prints first column

column == 0 or

# prints last column

column == n - 3 and (row != 0 and row != n - 1)

print("*", end=" ")

else:

print(" ", end="")

print()

# Size of the letter

num = int(input("Enter the size \t"))

if num < 8:

print("Enter a number atleast 8")

else:

print_pattern(num)

Output:

Pattern D - Pattern Programming - programminginpython.com — Pattern D – Pattern Programming – programminginpython.com

Letter D - Pattern Programming - programminginpython.com — Pattern D – Pattern Programming – programminginpython.com

Print Pattern D – Code Visualization

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Program on Github

Feel free to look at other letters in this pattern series here https://www.youtube.com/playlist?list=PLrKr3rQwMgsiLQ__JeCz_Vvr5pbk6pILT