Converting input arrays to output arrays starting at a particular index

[rishabhdhwaj]

Input:

{
    "order": {
        "order_items": [
            {
                "id": "1",
                "name": "one"
            },
            {
                "id": "2",
                "name": "two"
            }
        ],
        "default_item": {
            "id": "0",
            "name": "zero"
        }
    }
}

Desired output:

{
  "invoices" : [ {
    "id" : "1",
    "name" : "one"
  }, {
    "id" : "2",
    "name" : "two"
  }, {
    "id" : "0",
    "name" : "zero"
  } ]
}

I am achieving this by using the following spec:

[
    {
        "operation": "shift",
        "spec": {
            "order": {
                "order_items": {
                    "*": {
                        "id": "invoices[&1].id",
                        "name": "invoices[&1].name"
                    }
                },
                "default_item": {
                    "id": "invoices[2].id",
                    "name": "invoices[2].name"
                }
            }
        }
    }
]

But the problem with the above spec is that the input array can have any number of elements.So I can not default the default element to third index like the above spec. I would rather place the default element at the 0 index and start the other elements from input array from index 1 of the output array. How do we do this. Thanks a lot for your help

[milosimpson]

You have to do one shift to get the items into an array in the order you want, by leveraging Shiftrs "order of operations". I.e. at the same level in the spec, Shiftr will always try to match a "literal" string before wildcard "*" type matches.

You can then do a 2nd shift to transform the internals of each item.

Spec :

[
    {
        "operation": "shift",
        "spec": {
            "order": {
                "order_*": {
                    "*": "items"
                },
                "default_item": "items"
            }
        }
    }
]

[rishabhdhwaj]

Thanks. Got it